10x^2+18x-4=3

Solution for 10x^2+18x-4=3 equation:

10x^2+18x-4=3

We move all terms to the left:

10x^2+18x-4-(3)=0

We add all the numbers together, and all the variables

10x^2+18x-7=0

a = 10; b = 18; c = -7;
Δ = b2-4ac
Δ = 182-4·10·(-7)
Δ = 604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{604}=\sqrt{4*151}=\sqrt{4}*\sqrt{151}=2\sqrt{151}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{151}}{2*10}=\frac{-18-2\sqrt{151}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{151}}{2*10}=\frac{-18+2\sqrt{151}}{20}
$